1462A - Favorite Sequence - CodeForces Solution


implementation two pointers *800

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Python Code:

test_cases = int(input())
total=[]
for test in range(test_cases):
    elements=int(input())
    sequence = list(map(int,input().split()))
    for index,number in enumerate(sequence):
        if len(sequence)==1:
            total.append(sequence[0])
            break
        if len(sequence)%2!=0:
            total.append(str(sequence[index])+" "+str(sequence[len(sequence)-index-1]))
            if len(sequence)-index-1 == index:
                str1=total[-1]
                total[-1] = str1.split(" ")[0]
                break
        else:
            total.append(str(sequence[index])+" "+str(sequence[len(sequence)-index-1]))
            if (len(sequence)-index-1) - index ==1:
                break
print(*total)

C++ Code:

#include<bits/stdc++.h>
using namespace std;
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        int n;
        cin>>n;
        int arr[n];
        for(int i=0; i<n; i++)
        {
            cin>>arr[i];
        }
        for(int i=0; i<n/2; i++)
        {
            cout<<arr[i]<<" "<<arr[n-i-1]<<" ";
        }
        if(n%2!=0)
        {
            cout<<arr[n/2];
        }
        cout<<endl;
    }
}


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